2m^2+16m=-12

Solution for 2m^2+16m=-12 equation:

2m^2+16m=-12

We move all terms to the left:

2m^2+16m-(-12)=0

We add all the numbers together, and all the variables

2m^2+16m+12=0

a = 2; b = 16; c = +12;
Δ = b2-4ac
Δ = 162-4·2·12
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{10}}{2*2}=\frac{-16-4\sqrt{10}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{10}}{2*2}=\frac{-16+4\sqrt{10}}{4}
$